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Solve: 3(x + 4) greater than or equal to x - 2 x greater than or equal to -7 x greater than or equal to 7 x less than or greater to -7 x greater than or equal to -3 at last please give me what's the correct option.
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@phi
3(x + 4) ≥ x - 2 can you "distribute" the 3 on the left side ?
ya it will be 3x + 12
so you have 3x+12 ≥ x - 2 can you add -x to both sides ?
you add -x to both sides like this 3x+ -x +12 ≥ x + -x - 2 now simplify
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What the correct option after that ? @M_Vamshi_Kumar_Reddy
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