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Expand the series and evaluate:
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\[\sum_{k=1}^{4}(2k-1)\]
a) 2 + 4 + 6 + 8 = 16 b) 1 + 3 + 5 + 7 = 16 c) 1 + 3 + 5 + 7 = 21 d) 2 + 4 + 6 + 8 = 20
2k-1 plug in k= 1 to get 1st term 2(1) -1 = .... ? plug in k= 2 to get 2nd term 2(2) -1 = .... ? plug in k= 3 to get 3rd term 2(3) -1 = .... ? lastly plug in k= 4 to get 4th term 2(4) -1 = .... ?
b) 1 + 3 + 5 + 7 = 16 thanks man !(:
correct! welcome ^_^
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