Question

solve picture is inserted

Answer 1

@mathstudent2000

Answer 2

what would be the LCD of the 2 fractions of the left?

Answer 3

6x?

Answer 4

well, it'd be both denominators multiplying each other in this case, that would be the LCD

Answer 5

$$\bf \large {
\frac{1}{x-2}-\frac{1}{x-3}=-\frac{1}{2}\\
\frac{(x-3)-(x-2)}{(x-2)(x-3)} = -\frac{1}{2}\\
\frac{x-3-x+2}{(x-2)(x-3)} = -\frac{1}{2}\\
\frac{-1}{(x-2)(x-3)} = -\frac{1}{2}
}
$$

now what would that give you cross multiplying?