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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. f(x) = (x-9)/(x+5) and g(x) = (-5x-9)/(x-1)
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\[f(x)=\frac{x-9}{x+5}\\ g(x)=-\frac{5x+9}{x-1}\] \[\begin{align*}f(g(x))&=\frac{\left(-\dfrac{5x+9}{x-1}\right)-9}{\left(-\dfrac{5x+9}{x-1}\right)+5}\\\\\\ &=-\frac{\dfrac{5x+9}{x-1}+9}{5-\dfrac{5x+9}{x-1}}\\\\\\ &=-\frac{x-1}{x-1}\cdot\frac{(5x+9)+9(x-1)}{5(x-1)-(5x+9)}\\\\\\ &=-\frac{14x}{-14}\\\\\\ &=x\end{align*}\] Showing \(g(f(x))=x\) is a very similar process.
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