The figure shows triangle ABC with medians AF, BD, and CE. Segment AF is extended to H in such a way that segment GH is congruent to segment AG.
Which conclusion can be made based on the given conditions?
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OpenStudy (anonymous):
its not showing the pic?
OpenStudy (anonymous):
OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
now the conclusions..... :)
OpenStudy (anonymous):
Segment GD is congruent to segment GF.
Segment GD is parallel to segment HC.
Segment GF is parallel to segment EB.
Segment BH is congruent to segment HC.
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OpenStudy (anonymous):
hold on im thinking :)
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so do you know what parallel means?
OpenStudy (anonymous):
because we can eliminate one of the parallel choices by jst looking at it
OpenStudy (anonymous):
we can eliminate Segment GF is parallel to segment EB, because they obviously cross at the top.
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OpenStudy (anonymous):
I think its Segment BH is congruent to segment HC.
because the bisecting line in the middle bisects it equally.