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Mathematics 17 Online
OpenStudy (anonymous):

The figure shows triangle ABC with medians AF, BD, and CE. Segment AF is extended to H in such a way that segment GH is congruent to segment AG. Which conclusion can be made based on the given conditions?

OpenStudy (anonymous):

its not showing the pic?

OpenStudy (anonymous):

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

now the conclusions..... :)

OpenStudy (anonymous):

Segment GD is congruent to segment GF. Segment GD is parallel to segment HC. Segment GF is parallel to segment EB. Segment BH is congruent to segment HC.

OpenStudy (anonymous):

hold on im thinking :)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so do you know what parallel means?

OpenStudy (anonymous):

because we can eliminate one of the parallel choices by jst looking at it

OpenStudy (anonymous):

we can eliminate Segment GF is parallel to segment EB, because they obviously cross at the top.

OpenStudy (anonymous):

I think its Segment BH is congruent to segment HC. because the bisecting line in the middle bisects it equally.

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

c how I got it?

OpenStudy (anonymous):

yes

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