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Mathematics 14 Online
OpenStudy (anonymous):

The probability distribution of successful free throws for a practice set is given below. Find the expected number of successes for one set.

OpenStudy (anonymous):

hartnn (hartnn):

Expectation E(X) = \(\sum x p(x)\) so, just multiply 'n' and probability of n good free throws for each entry!

hartnn (hartnn):

E(X) = 0*(3/20)+ ... + 3 (1/2) = ... ?

OpenStudy (anonymous):

0 + ... + 3/2

hartnn (hartnn):

include the 2 missing terms too :P

OpenStudy (anonymous):

1(3/20)+2(1/5)?

hartnn (hartnn):

yes! 0+3/20+2/5+3/2 is your expectation

OpenStudy (anonymous):

2.05 ... thanks(:

hartnn (hartnn):

welcome ^_^

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