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The probability distribution of successful free throws for a practice set is given below. Find the expected number of successes for one set.
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Expectation E(X) = \(\sum x p(x)\) so, just multiply 'n' and probability of n good free throws for each entry!
E(X) = 0*(3/20)+ ... + 3 (1/2) = ... ?
0 + ... + 3/2
include the 2 missing terms too :P
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1(3/20)+2(1/5)?
yes! 0+3/20+2/5+3/2 is your expectation
2.05 ... thanks(:
welcome ^_^
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