Question

Help please on the equation in the attachment.

Answer 1

can you find the inverse function ?

Range of a function is same as Domain of inverse function..

Answer 2

I'm not sure I understand that

Answer 3

y= 1/(x+2) -1
can you isolate x from this ?

Answer 4

As in set the x equal to 0?

Answer 5

no, try to bring 'x' in one side of = sign,
x= ....

as a start, you can add 1 to both sides, what u get ?

Answer 6

1+y=1/(x+2)
y+1=1/(x+2)

Answer 7

yes, now flip the fraction
y+1 = 1/(x+2)
gives
1/(y+1) = x+2
got this ?

Answer 8

now since denominator cannot be 0, which value does 'y' cannot take ?

Answer 9

-1?

Answer 10

good!
so, \(y\ne -1\)
so which option ?

Answer 11

D.
Thank you!

Answer 12

welcome ^_^