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what is 4=16^x / 4^x ?????????
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\[4 = \frac{ 16^x }{ 4^x }\] It looks like we can simplify the right side pretty nicely. Any ideas?
\(\bf 4 = \cfrac{16^x}{4^x} \implies 4\times 4^x = 16^x\\ 4^{x+1} = 16^x\)
from there try to use the log cancellation rule of => \(\bf\huge log_aa^x = x\)
confused still @vramirez83 ?
I think this problem is made easier by noticing that 16^x / 4^x = 4^x So, we have 4^x = 4 instead of taking a log here, what number (x), gives us 4 when we take 4 to the x power?
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no i got it thank you (:
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