Question

In triangle ABC, ∠A = 80°. The bisectors of the base angles, ∠B and ∠C, intersect at point P.
∠BPC =


50°
100°
130°

Answer 1

draw a diagram

well you know B + C = 180 - 80

so B + C = 100

if both B and C are bisected then the measure of

1/2 (B + C) = 50

so using angle sum of a triangle

BPC = 180 - 1/2 (B + C)

I'll leave you to get the final answer

Answer 2

thanks