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Give a medal ? 4* e^x = 17
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\(\bf lnx = log_ex\)
divide both sides by 4 then take the base e log of both sides
\(\bf 4e^x=17 \implies e^x= \cfrac{17}{4}\\ log_ee^x = log_e\left(\cfrac{17}{4}\right) \implies x = ln\left(\cfrac{17}{4}\right)\\ x = ln(17)-ln(4) \)
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