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Mathematics 20 Online
OpenStudy (anonymous):

how do i complete a the square and add how to solve by graphing, this is what i got so far and now i am lost: 6. X^2-6x+9=0 (x-3)^2=0 X=3 X^2-6x=-9 (x-3)^2-9=-9 (x+3)^2=0 (6+-sqrt6^2-4*9)/2 6/2 3

OpenStudy (anonymous):

@terenzreignz @whpalmer4 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

x^2-6x+9 is already a perfect square so there's no need to complete the square

jimthompson5910 (jim_thompson5910):

but you are correct in saying that (x-3)^2 = 0 x = 3

OpenStudy (anonymous):

ok thank you my teacher i didnt finish the square bit i knew i did i just wanted to double check.

jimthompson5910 (jim_thompson5910):

yw

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