how do i complete a the square and add how to solve by graphing, this is what i got so far and now i am lost:
6. X^2-6x+9=0
(x-3)^2=0
X=3
X^2-6x=-9
(x-3)^2-9=-9
(x+3)^2=0
(6+-sqrt6^2-4*9)/2
6/2
3

Question

how do i complete a the square and add how to solve by graphing, this is what i got so far and now i am lost:
6.	X^2-6x+9=0
(x-3)^2=0
X=3
X^2-6x=-9
(x-3)^2-9=-9
(x+3)^2=0
(6+-sqrt6^2-4*9)/2
6/2
3

anonymous · Answer

@terenzreignz 
@whpalmer4 
@jim_thompson5910

jim_thompson5910 · Answer

x^2-6x+9 is already a perfect square

so there's no need to complete the square

jim_thompson5910 · Answer

but you are correct in saying that

(x-3)^2 = 0

x = 3

anonymous · Answer

ok thank you my teacher i didnt finish the square bit i knew i did i just wanted to double check.

jim_thompson5910 · Answer

yw