integral of sqrt(x)/(1+x^3)
you would like to set \[x^{3/2}\]
\[u=x^{2/3}\]
how did you know how to do that? Because i was trying to figure it out and couldnt
if u set u=x^{3/2} du would be 3/2x^1/2
i first tried integration by parts but that didnt work
let me write it good lol
im taking calc 2 right now and its hard to try to figure out which technique to use when solving integrals
\[u=x^{3/2}\] \[du=\frac{ 3 }{ 2 }\sqrt[]{x}dx\]
so now u can substitude in the integral
yeah it worked.
sometimes its not very obvious to see the substitution but with more problem solving u get idea what to do xD
ok thanks!
no problem :)
have you take calc 2 yet?
yes i have , calc 3 right now
oh ok, im taking that in the fall. any suggestions when trying to solve integrals?
i can just recomend you this site wolframalpha if u dont know it yet , can help you a LOT it did quite good job for my maths , and for solving integrals i am not quite sure what to suggest you its mostly about practise and facing more and more different integrals and u'll get the idea :) good luck
ok thanks! take care
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