HELP :)
The shaded area in the diagram below shows the cross section of a pyramid intersected by a plane that passes through the apex and is perpendicular to the base. The base of the pyramid is a square of side 10 cm. Each edge of the triangular faces is 15 cm long.
Which is the best approximation of the perimeter of the cross section?
38 cm
40 cm
32 cm
42 cm
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
first solve for x in the equation below
x^2 + 5^2 = 15^2
and tell me what you get
OpenStudy (anonymous):
x^2+25=225
jimthompson5910 (jim_thompson5910):
so far, so good
jimthompson5910 (jim_thompson5910):
what's next?
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OpenStudy (anonymous):
Corresponding image to @jim_thompson5910 's algebra
|dw:1374287184332:dw|
OpenStudy (anonymous):
x^2=200 ??
jimthompson5910 (jim_thompson5910):
so if x ^2 = 200, then what is x
OpenStudy (anonymous):
i dont know :/
jimthompson5910 (jim_thompson5910):
what undoes the square exponent?
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OpenStudy (anonymous):
division?
OpenStudy (anonymous):
x=100?
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
no if you had 2x = 200, then you would be correct
jimthompson5910 (jim_thompson5910):
but division does NOT undo squaring
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jimthompson5910 (jim_thompson5910):
square roots undo squaring
OpenStudy (anonymous):
so im not sure what to do next? square root of 200?
jimthompson5910 (jim_thompson5910):
yep you got it
jimthompson5910 (jim_thompson5910):
so, that's the slant height
OpenStudy (anonymous):
14.14 isnt one of my options :/
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jimthompson5910 (jim_thompson5910):
you add up
14.14 + 14.14 + 10
jimthompson5910 (jim_thompson5910):
you have 2 lengths that are sqrt(200) = 14.14 units long of this triangle