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Mathematics 11 Online
OpenStudy (anonymous):

HELP :) The shaded area in the diagram below shows the cross section of a pyramid intersected by a plane that passes through the apex and is perpendicular to the base. The base of the pyramid is a square of side 10 cm. Each edge of the triangular faces is 15 cm long. Which is the best approximation of the perimeter of the cross section? 38 cm 40 cm 32 cm 42 cm

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

first solve for x in the equation below x^2 + 5^2 = 15^2 and tell me what you get

OpenStudy (anonymous):

x^2+25=225

jimthompson5910 (jim_thompson5910):

so far, so good

jimthompson5910 (jim_thompson5910):

what's next?

OpenStudy (anonymous):

Corresponding image to @jim_thompson5910 's algebra |dw:1374287184332:dw|

OpenStudy (anonymous):

x^2=200 ??

jimthompson5910 (jim_thompson5910):

so if x ^2 = 200, then what is x

OpenStudy (anonymous):

i dont know :/

jimthompson5910 (jim_thompson5910):

what undoes the square exponent?

OpenStudy (anonymous):

division?

OpenStudy (anonymous):

x=100?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

no if you had 2x = 200, then you would be correct

jimthompson5910 (jim_thompson5910):

but division does NOT undo squaring

jimthompson5910 (jim_thompson5910):

square roots undo squaring

OpenStudy (anonymous):

so im not sure what to do next? square root of 200?

jimthompson5910 (jim_thompson5910):

yep you got it

jimthompson5910 (jim_thompson5910):

so, that's the slant height

OpenStudy (anonymous):

14.14 isnt one of my options :/

jimthompson5910 (jim_thompson5910):

you add up 14.14 + 14.14 + 10

jimthompson5910 (jim_thompson5910):

you have 2 lengths that are sqrt(200) = 14.14 units long of this triangle

OpenStudy (anonymous):

38.28 :)

OpenStudy (anonymous):

thankyou !

jimthompson5910 (jim_thompson5910):

yw

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