Question

Find the approximate value of cube root of 127.

Answer 1

Attempt:
\[\Huge f(x)=(x)^\frac{1}{3}\]
\[\LARGE f(x+\Delta x)=f(x)+\Delta x(f'(x))\]
this is the derived formula..
substituting x=125 and delta x=2
\[\LARGE f(127)=f(125)+2 \times \frac{1}{3} \times (\frac{1}{125})^{\frac{2}{3}}\]

Answer 2

\[\LARGE \frac{50}{3}+5=>\frac{65}{3}?\]

Answer 3

hmm seems wrong :P

Answer 4

@DLS \(2\times\frac13\times(\frac1{125})^\frac23\ne\frac{50}3\)

Answer 5

2/3 x 1/25 sorry!!

Answer 6

2/75

Answer 7

You incorrectly simplified \((1/125)^{2/3}=25\) rather than \(1/25\)

Answer 8

\[\LARGE 5+\frac{2}{75}=377/75\]