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Mathematics 22 Online
OpenStudy (anonymous):

multiply √12x√3xy^2 is the answer 6x?

OpenStudy (anonymous):

is the 2nd part (√3xy)^2?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

then?

OpenStudy (anonymous):

√12x√3xy^2

OpenStudy (anonymous):

so only 3x is under the radical?

OpenStudy (anonymous):

|dw:1374309983533:dw|

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