Question

int x=1; printf("%d%d%d",x,x++,++x); what is the output and how?

Answer 1

--> all the arguments of a function(printf) are evaluated before being passed
--> This order in which these arguments are evaluated relative to each other is unspecified

--> This order of evaluation is dependent on the compiler and sometimes a compiler may also choose different order

Conclusion : such statement`s behavior is undefined.