(x+2)/(x+4) = 3/x When I solved for x, I got x=3 and 4. Am I correct?
ok but when there is x on denominator what is the first step ,what is the restriction what we need taking for x ?
do you know it ?
so when is a fraction undefined ?
when the denominator = 0?
yes so than what will be the restriction value for x ?
can you calculi it ?
I don't really understand...
you have said that a fraction is undefined when the denominator is equal zero so there are 3 fractions with 3 denominators with x so for these denominators dont being equal zero what values not can getting x how can you calculi these values ?
sorry not 3 just two
ok what are the denominators of these two fractions ?
x+4 and x
yes so x+4 and x when will be equal zero ,when x is equal what value ?
-4 and 0?
yes right so these are the restrictions for x ok ?
Yeah, okay.
so than now (x+2)/(x+4) = 3/x because there are two fractions with two different denominators what you need to do ?
find common denominators?
yes is right but you can solve it by different ,easy style so like ,,cross multiplie" yes ?
what you will get than ?
Yeah. x^2 + 2x over 3x-12
(x+2)/(x+4) = 3/x cross multiplie how you get ,,over" ?
x+2 3 ---- = --- x+4 x cross multiplie what mean ?
over is the fraction. (x^2+2x)/(3x-12)
yes i understand it right but not is correct so what mean cross multiplie when there is x+2 3 ---- = --- x+4 x ...???
You multiply x+2 and x. Then you multiply x+4 and 3. Right?
yes ,please write these here now
x(x+2)=3(x+4) yes ? than make the calculi
then it would equal x^2+2x = 3x - 12
not is right
What did I do wrong?
check it step by step term by term
x(x+2)=3(x+4) x(x+2) = ?
comen i like make you giving where not is right
how you have got on the right side - 12 ?
Distributive property. 3(x-4). 3(x) -3(4).
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