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Mathematics 20 Online
OpenStudy (anonymous):

Please help!! Linear Algebra.

OpenStudy (anonymous):

OpenStudy (anonymous):

finding determinant

OpenStudy (anonymous):

@surjithayer are you really typing up a reply.. i'm hopeful.

OpenStudy (anonymous):

|dw:1374347764123:dw| =(b-a)(c-a){1(c+a)-1(b+a)} =(b-a)(c-a)(c+a-b-a)=(b-a)(c-a)(c-b)=(a-b)(b-c)(c-a) write a1 for a,a2 for b, a3 for c and get the required solution.

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