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Mathematics 21 Online
OpenStudy (highschoolmom2010):

solve for x

OpenStudy (highschoolmom2010):

ganeshie8 (ganeshie8):

altitude = geometric mean of segments of hypotenuse

ganeshie8 (ganeshie8):

All the problems you've been dealing with are basically related to geometric mean only

ganeshie8 (ganeshie8):

you may do these using similar triangles approach as you've learned them in geometry already. but since all are geometric mean related, i would guess your teacher wants you do these using geometric mean thingy

OpenStudy (highschoolmom2010):

so i am pretty much doing what i kinda did with the other ones

ganeshie8 (ganeshie8):

you wanto do these using similar triangles or you wanto do these using geometric mean ?

ganeshie8 (ganeshie8):

pick one

OpenStudy (highschoolmom2010):

geometric mean

ganeshie8 (ganeshie8):

cool then its easy, you dont have to setup a proprtion

ganeshie8 (ganeshie8):

altitude = geometric mean of segments of hypotenuse

OpenStudy (highschoolmom2010):

when we are done can we try doing it the other way

ganeshie8 (ganeshie8):

okay lets do both, Lets first do geometric mean

ganeshie8 (ganeshie8):

altitude = x+5

ganeshie8 (ganeshie8):

segments of hypotenuse = x, 20

ganeshie8 (ganeshie8):

altitude = geometric mean of segments of hypotenuse \(x+5 = \sqrt{x \times 20}\)

ganeshie8 (ganeshie8):

thats how we take geometric mean right ? (multiply both, take square root)

OpenStudy (highschoolmom2010):

i think so

ganeshie8 (ganeshie8):

square both sides solve x

OpenStudy (highschoolmom2010):

ok ^^ wouldnt that cancel out sqrt

ganeshie8 (ganeshie8):

yes it wud

OpenStudy (highschoolmom2010):

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