Question

Please help me set-up the following double integral using polar coordinates (click to see).

Answer 1

The portion of the sphere:
\[z=\sqrt{16-x^2-y^2}\]

between the planes:
z=1
and
z=2

Answer 2

My problem is setting up the limits of integration.

Answer 3

\[\int\limits_{}^{}\int\limits_{}^{}(\sqrt{16-r^2})rdrd \theta\]