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Find a˅13 when a˅1= -3 and d=2
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So you recall the geometric formula \[an = ar ^{n-1}\] so r = 2 and a1 = -3
I cannot tell what sign that is
here solve this for an.. \[an = (-3)(2)^{13-1}\]
-6\[^{12}\]
-6^12
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No remember your bedmass
so what is 2^12?
4069
so now what is -3 x 4069 ?
-12207
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Try again....
I keep getting -12207
|dw:1374391565599:dw| your right
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