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For the pair of functions f(x)=3x and g(x)=3x^2-4x+6 find the following: (f o g)(x) (f o g)(3) (g o f)(x) (g o f)(-1)
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(f o g)(x) substitute g(x) in every x in f(x), so you have, f(x)=3x sub in g(x) at x f(x)=3(3x^2-4x+6)=9x^2-12x+18
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