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the perimeter of a rectangle equals the sum of the lengths of its four side. if the width of rectangle is 8 inches and its perimeter is 40 inches, find the length of the rectangle.
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im lost
Let the length be L Let the width be W Let the perimeter be P P = L + L + W + W Right?
P=2L+2W
That's good. Now substitute all variables you know by the numbers you are given: W = 8 and P = 40
40 = 2L + 2(8) Now solve for L
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16
\(16 + 16 + 8 + 8 \ne 40 \)
im lost
\(40 = 2L + 2(8)\) \(40 = 2L + 16\) \(24 = 2L\) \(12 = L\) The length is 12 inches.
8
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primeralph what you want me to do
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