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Express the area of ∆ABD in terms of θ:
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((1-cosθ)sinθ)/2
How???
1/OC = OD cosθ=1/OC OD=cosθ BD=sinθ the area of ABD (triangle only) is AD*BD/2 AD=1-OD=1-cosθ so [ABD]=((1-cosθ)sinθ)/2
Express the area of the shaded region in terms of θ. Hint: If A is the area of the sector of a circle, \[A = \frac{ r ^{2}\theta }{ 2 }\] where r is the radius of the circle and θ is the central angle.
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