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Mathematics 17 Online
OpenStudy (anonymous):

Find the standard form of the equation of the hyperbola with the given characteristics vertices: (0, ±3) foci: (0, ±6)

OpenStudy (anonymous):

((y^2)/36)-((x^2)/27)

OpenStudy (anonymous):

Hold on, no, it's actually ((y^2)/9)-((x^2)/27)

OpenStudy (anonymous):

but are you sure the VERTICES, not COVERTICES are (0, +-3)?

OpenStudy (anonymous):

yeah and thats the answer i thought, thanks!

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