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Find the indicated nth term of the geometric sequence: 7th term
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$$ \color{blue}{n^{th} = \cfrac{-3}{(-2)^{n-1}}}\\ a_5 = \cfrac{-3}{(-2)^{5-1}} \implies \cfrac{-3}{(-2)^{4}} =\cfrac{-3}{16}\\ a_10 = \cfrac{-3}{(-2)^{10-1}} \implies \cfrac{-3}{(-2)^{9}} = \cfrac{-3}{-512} = \cfrac{3}{512} $$
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