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Mathematics 9 Online
OpenStudy (anonymous):

Find AB. Round to the nearest tenth. a. AB = 14.5 b. AB = 13.8 c. AB = 10.4 d. AB = 33.8 Thank you to anyone who helps me with this problem!

OpenStudy (anonymous):

OpenStudy (anonymous):

Well it's a kinda known reward for helping that one would get a medal and/or fan, but anyways this a SSA triangle, you can solve using the law of Sines, doy ou know what that is?

OpenStudy (anonymous):

Yeah I know!

OpenStudy (anonymous):

|dw:1374455542225:dw| OK well remeber that an angle is an uppercase letter and its side is opposite form it like this

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

\[\frac{ 12 }{ \sin 50~degrees }=\frac{ x}{ \sin 62~degrees }\]

OpenStudy (anonymous):

That propotion can be solve for x (AB) since \[\frac{ a }{ SinA }=\frac{b }{ SinB }=\frac{ c }{ SinC }\]

OpenStudy (anonymous):

Okay, I got the answer 14.5.

OpenStudy (anonymous):

Are you sure ?

OpenStudy (anonymous):

\[\frac{ 12 }{ \sin 50~degrees }=\frac{ x}{ \sin 62~degrees }\]

OpenStudy (anonymous):

Not really, what did you get?

OpenStudy (anonymous):

Nevermind

OpenStudy (anonymous):

sorry my computer restarted, diud you get 13,8?

OpenStudy (anonymous):

That's okay, I got that too thank you

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