Find AB. Round to the nearest tenth. a. AB = 14.5 b. AB = 13.8 c. AB = 10.4 d. AB = 33.8 Thank you to anyone who helps me with this problem!
Well it's a kinda known reward for helping that one would get a medal and/or fan, but anyways this a SSA triangle, you can solve using the law of Sines, doy ou know what that is?
Yeah I know!
|dw:1374455542225:dw| OK well remeber that an angle is an uppercase letter and its side is opposite form it like this
Alright
\[\frac{ 12 }{ \sin 50~degrees }=\frac{ x}{ \sin 62~degrees }\]
That propotion can be solve for x (AB) since \[\frac{ a }{ SinA }=\frac{b }{ SinB }=\frac{ c }{ SinC }\]
Okay, I got the answer 14.5.
Are you sure ?
\[\frac{ 12 }{ \sin 50~degrees }=\frac{ x}{ \sin 62~degrees }\]
Not really, what did you get?
Nevermind
sorry my computer restarted, diud you get 13,8?
That's okay, I got that too thank you
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