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Mathematics
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//H̴̙̓͛̊ͮ̒ͣ̽E̠̦̟̝̣̥͂L̿̂͞ͅP̳̊̅ͬ ̄̊̌͌Fͪ̀A̛S̗̒ͮ̑̾T̷̜̺̜̰̻͔̃̃͑̽ͦ̎ͅ show steps if you can!!!// Write the quadratic function c(x)=x^2-8x-17 in vertex form.
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so we must complete the square? do you know how to do that?
Not really, to be honest...
\[x^2-x-17=0\] we bring the 17 on the right hand side by adding both sides by 17 \[x^2-8x=17\] Now we divide the coefficient of the x term by 2 and add it to both sides \[x^2-8x+(-\frac{ 8 }{ 2 })^2=17+(-\frac{ 8 }{ 2 })^2\] Now we simplify this into vertex for as follows... \[(x-4)^2=33\] which implies \[y=(x-4)^2-33\] is ur vertex form for that equation
@arachnidsGrip
thank you! :)
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np :)
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