Question

use the Laplace transform to solve the
given system of differential equations.

2x''=-6x+2y
y''=2x-2y+40sin3t

where x(0)=x'(0)=y(0)=y'(0)=0
i applied Laplace transform and got

1-> X(s){s^2-s+2}-2Y(s)=0
2-> Y(s)(s^2-s+2)-2x(s)= 40{3/(s^2+3^2)}

now how would i solve stuck i know its basic algebra but need help