Question

Matrix questions?!?

Answer 1

yes please

Answer 2

\[\mathbf A=\begin{bmatrix}4,-2\\-3,10\end{bmatrix}\]\[\mathbf C=\begin{bmatrix}3,2\\0,-9\end{bmatrix}\]

Answer 3

\[2\mathbf A=2\begin{bmatrix}4,-2\\-3,10\end{bmatrix}=\begin{bmatrix}2\times4,2\times-2\\2\times-3,2\times10\end{bmatrix}\]
\[-3\mathbf C=\begin{bmatrix}3,2\\0,-9\end{bmatrix}=-3\begin{bmatrix}3,2\\0,-9\end{bmatrix}=\begin{bmatrix}-3\times3,-3\times2\\-3\times0,-3\times-9\end{bmatrix}\]
\[2\mathbf A-3\mathbf C=\quad\dots\]

Answer 4

This makes no sense..... :(

Answer 5

*sorry typo*
\[-3\mathbf C=-3\begin{bmatrix}3,2\\0,-9\end{bmatrix}=\begin{bmatrix}-3\times3,-3\times2\\-3\times0,-3\times-9\end{bmatrix}\]

Answer 6

I don't think I'll even begin to understand this.. I'm just going to guess. Thanks, though.

Answer 7

What bit dont you understand/
?

Answer 8

All of it. My math education is equivalent to a 12 year old.

Answer 9

some examples

When adding matricies of the same size, just add the corrsponding elements \[\begin{bmatrix}\color{goldenrod}3&\color{goldenrod}{-2}\\\color{goldenrod}4&\color{goldenrod}{-3}\end{bmatrix}+\begin{bmatrix}\color{teal}{-5}&\color{teal}{-4}\\\color{teal}3&\color{teal}{-2}\end{bmatrix}\\=\begin{bmatrix}(\color{goldenrod}3\color{teal}{-5})&(\color{goldenrod}{-2}\color{teal}{-4})\\(\color{goldenrod}4+\color{teal}3)&(\color{goldenrod}{-3}\color{teal}{-2})\end{bmatrix}=\begin{bmatrix}12&-42\\-18&24\end{bmatrix}\]

when we multiplying a matrix by a scalar we simply multiply every element\[\color{salmon}6\begin{bmatrix}2&-7\\-3&4\end{bmatrix}=\begin{bmatrix}\color{salmon}6\times2&\color{salmon}6\times-7\\\color{salmon}6\times-3&\color{salmon}6\times4\end{bmatrix}=\begin{bmatrix}12&-42\\-18&24\end{bmatrix}\]

Answer 10

do these examples make any sense to you ?