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Mathematics 15 Online
OpenStudy (anonymous):

If f(x) = │(x² - x - 15)│, what is the value of f(3) ?

OpenStudy (anonymous):

replace all of x with the 3, then solve

OpenStudy (anonymous):

what about modulus

OpenStudy (anonymous):

f(3) = │(3² - 3 - 15)│

OpenStudy (anonymous):

answer 9

OpenStudy (anonymous):

is it correct ?

OpenStudy (anonymous):

hang on

OpenStudy (anonymous):

yes. |-9| = 9 is correct.

OpenStudy (anonymous):

but i think ur answer needs to be f(3)=9

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