Help with these triangle problems? Thanks in advance!!

1. A triangle has angle measure of 40°, 59°, and 81°.
The side opposite of the 40° angle is 11cm long. Find the lengths of the side opposite the 81° angle to the nearest centimeter.

2. Given triangle ABC with a=14, A=25°, B=17, find c. Round to the nearest whole number.

3. Solve triangle ABC given that a=12, b=19, c=21. Round to the nearest degree.

Thanks, again.

Question

Help with these triangle problems? Thanks in advance!!

1. A triangle has angle measure of 40°, 59°, and 81°.
The side opposite of the 40° angle is 11cm long. Find the lengths of the side opposite the 81° angle to the nearest centimeter.

2. Given triangle ABC with a=14, A=25°, B=17, find c. Round to the nearest whole number.

3. Solve triangle ABC given that a=12, b=19, c=21. Round to the nearest degree.

Thanks, again.

zzr0ck3r · Answer

do you know about law of sines?

anonymous · Answer

@zzr0ck3r No :(

anonymous · Answer

Is there a formula for the law of sines?

anonymous · Answer

@zzr0ck3r

zzr0ck3r · Answer

sorry, um yeah but if you are not supposed to use it, then we should use some other method...what are you doing in class?

anonymous · Answer

This is actually an online class

zzr0ck3r · Answer

what are you doing in the online class?

zzr0ck3r · Answer

if you want to use law of sines then here is how it works
|dw:1374475176027:dw|

sin(a)/A = sin(b)/B = son(c)/C

zzr0ck3r · Answer

you have a = 40 and A = 11, and b = 81
so
sin(40)/11 = sin(81)/x
solve for x
x=11*sin(81)/sin(40)