Let x,y,z be the real roots of the cubic equation 2u^3−799u^2−400u−1 and let ω=tan−1x+tan−1y+tan−1z. If tanω=ab, where a and b are positive coprime integers, what is the value of a+b?
@killua_vongoladecimo: Have u tried it bro ??
nah
K I"ll give u a hint Use identity tan−1(x)+tan−1(y)=tan−1[(x+y)/(1-xy)] U should try it from here on . This is a nice Question
um..would you guide me?
should i get the roots of the cubic equation? if ever i will how ?
@Anu2401
Yes. If u proceed as mentioned above u will get tan(w) in terms of xyz . Which are the roots of given equation.
Just solve that equation first .
to tell you the truth i dont know what tan is XD so as much as possible guide me as much as you can without giving the answer
how to extract it's roots? is it composed of binomial?
Do u know the theory of cubic equations ??
nope
Ok wait
ok :)
I hv attached the theory part for any order of equation . This will help u .. Always remember this .It is going to be very helpful to know this one. Have a look
um...what does alpha,beta, and the greek y represent?
Here in ur case these are x y z which are the roots of the given equation au^3+bu^2+cu+d where a, b , c , d are some constant values here a=2, b=-799,c=-400 & d=-1
ummm... i really don't get it
ummm..what book did u use?
Have a look in attachment after the word "In Particular " written in bold OKwhat do u understand after reading that much .. Let me know
there's alpha,beta and greek y right? what do those symbolize?
um form what country are you?
i kinda need to go now...let's continue tomorrow
or just write the explanation i'll just look at it and review it
You can represent a variable with whatever symbol you like be it alpha,beta and gama or xyz they are the same
um can you solve it... as in with full explanation it's about 11:22 pm here i'll just look at it and write the solution is that ok?
Ok
um do you have facebook?
Yes
is it ok if i add you?
btw from what country are you?
Yup
India
what's yur name in facebook?
what is the time there?
8:30 PM
what's yur facebook name?
bye
Bye
@killua_vongoladecimo : Have a look . Go through theory . And try to proceed from there
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