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Someone please help Verify the identity cot ( θ - pi/2) = - tan θ
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ok i will...:)
what is cot(x-y)?...cotxcoty+1/coty-cotx...right?
put x=theta and y=pi/2
we get \[\cot(\theta-\pi/2)=\cot \theta.(\cot \pi/2)/(\cot \pi/2)-\cot \theta\]
cot pi/2=0..
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we get the answer as 1/-cot theta which is -tan theta
thanks
My pleasure @Aurelia0912
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