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Precalculus
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If you help, I'll give you a medal :D Verify the identity. cot(x- pi/2) = -tan x
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thats easy i will help
Thank you sooooooo much!!
cot(x-y)=cotx.coty+1/coty-cotx
put x=x and y=pi/2
this gives \[\cot(x-\pi/2)=cotx.\cot(\pi/2)/\cot(\pi/2)-cotx\]
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ok?
there is a '+1' in the numerator i forgot to type
ok
cot pi/2=0
this gives 1/0-cotx=-tanx
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hence the proof
got it??
need more explanation??
I think I got it! Thank you!!!
be sure..
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lol any doubts...ask me:)
ok, thank you :D
my pleasure:D
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