Question

find the area of this triangle to find b

Answer 1

? helpss

Answer 2

\[25+100+c=180,c=180-125=55\]
draw perpendicular from A on BC.
\[area A=\frac{ 1 }{ 2 }*42*h=21h\]
\[\frac{ h }{ b }=\sin 55,h=b \sin 55\]
A=21b sin 55
by sin formula
\[\frac{ b }{ \sin 25 }=\frac{ 42 }{ \sin 100},b=42*\frac{ \sin 25 }{ \sin 100 }\]
\[A=21*42*\frac{ \sin 25\sin 45 }{ \sin 80 }\]
you can find the value of A and b