Question

NEED HELP PLEASE!!
Factor the GCF and then factor the resulting binomial: 50x3 - 128x
A. 2x(5x + 8)(5x - 8)
B. 2x(5x + 64)(5x - 64)
C. x(25x + 64)(25x - 64)
D. 5x(2x + 8)(2x - 8)

Answer 1

GCF between 50 and 128 = ??
between x^3 and x = (always the smallest one)

Answer 2

I DONT NOW

Answer 3

DO YOU NOW THE ANSWER?

Answer 4

yes, I do, but want to see if you can figure it out.

between 50 and 128 the GCF = 2 so you take out 2x
and you have

2x(25x^2-64)

Answer 5

now you can simplify the (25x^2-64) as (a^2-b^2) = (a+b)(a-b)

Answer 6

THAT IS NOT IN THE SELECTION IS IT A B C OR D?????

Answer 7

did you simplify as shown

Answer 8

it is on the selection

Answer 9

YES BUT I DONT GET THE ANSWER!

Answer 10

ok you have 25x^2 - 64
that is the same as (5x)^2 - 8^2
if you look at the formula that is (5x+8)(5x-8), so the answer would be

2x(5x+8)(5x-8)

Answer 11

Here's how you factor it:

50x^3 - 128x
2x(25x^2 - 64)
2x(25x^2 + 40x - 40x - 64)
2x(5x(5x + 8) -8(5x + 8))
2x((5x + 8)(5x - 8))
2x(5x + 8)(5x - 8)

Answer 12

If you want to know exactly how I did that, let me know.

Answer 13

The secret is this:

mn = -1600
m + n = 0

(-40)(40) = -1600
-40 + 40 = 0