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Evaluate f(x) = 8 sin x − 6 cos 2x at x = π/6. 1. f(π/6) = 3√3 2. f(π/6) = 1 3. f(π/6) = 2√3 4. f(π/6) = 2 5. f(π/6) = √3 6. f(π/6) = 3
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\[\sin \left( \frac{ \pi }{6 } \right) = \frac{ 1 }{ 2 }\]
\[\cos \left( \frac{ 2\pi }{ 6} \right) = \cos \left( \frac{ \pi }{ 3} \right) = \frac{ 1 }{ 2}\]
We know this from the unit circle.
\[8\left( \frac{ 1 }{ 2 } \right) - 6\left( \frac{ 1 }{ 2 } \right)\]
4-3 = 1
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