**PLEASE HELP, I'M DESPERATE *** Brayden is investing $1,617 in three different stocks: Zycodec, Unix, and Xenon. He will invest 40% of the total between Zycodec and Xenon in the Unix stock. Twice as much as the investment in Zycodec will be given to Xenon. How much will Brayden invest in the Unix stock? A. $385 B. $462 C. $770 D. $924
I don't understand this line "He will invest 40% of the total between Zycodec and Xenon in the Unix stock"
:/
OMGGGGGG IHATE MATHHHHHHHHHH
lol
are you sure those are the exact words?>
Yes, why wouldn't they be? I copied and pasted
well, I get this Z + X = SOME AMOUNT U = 40% SOME AMOUNT => U = (Z+X)0.4 now twice as much of Z goes to X so X = 2Z
ahh ok I see what its saying
so Z + X + U = 1617 but X = \(\color{blue}{2Z}\) and U = (Z + X) => ( Z + \(\color{blue}{2Z}\))
hmm, actually and U = (Z + X) => ( Z + \(\color{blue}{2Z}\))(0.4)
which is 40% of the total of Zycoden and Xenon stocks
so Z + X + U = 1617 or Z + 2Z + (Z + 2Z)(0.4) = 1617 then just solve for "Z"
omfg
hehe
z + 2z + (z+2z)(0.4)
Lower case makes it better but I still don't understand
once you find Z, zycodec amount to get Unix stock amount, well, U = (Z + 2Z)0.4
Idk how to find z
is just plain simplifying
the Xenon stock is based on the Zycodec, 2 to 1, so Xenon's is twice as much or 2Z the total amount invested in Zycodec and Xenon is , Zycodec's plus Xenon or Z + 2Z
and the Unix stock is based on their total, 40% of it
B. $462 ????
yes
Zycodec's amount is $385 thus 0.4 or 2/5 2/5 ( 385 + 770) => 462
Join our real-time social learning platform and learn together with your friends!