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Mathematics 16 Online
OpenStudy (anonymous):

Factor: 2x2 + 10x - 100

OpenStudy (anonymous):

you are trying to get this into 2 polynomials yes?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so you are going to turn this into (2x +/- ?)(x +/- ?)

OpenStudy (anonymous):

so the sum of the w ? has to equal 10, but multiply to 100

hero (hero):

Factor out the 2 first

OpenStudy (anonymous):

2(x+10)(x-100)?

OpenStudy (anonymous):

understand?

hero (hero):

2(x^2 + 5x - 50)

OpenStudy (anonymous):

wait no 2(x-10)(x+10)

hero (hero):

That's the factoring short cut, but it's not all the factoring steps.

OpenStudy (anonymous):

no no do you know how to factor x^2 + 5x - 14?

OpenStudy (anonymous):

yes yes that is the correct answer, except the 2 will be in the first binomial

hero (hero):

@D_ , what you posted was not correct.

OpenStudy (anonymous):

i wrote it as 2(x+5)(x-10) than i got (2x+10)(x-10) which is now 2x^2-20+10x-100

OpenStudy (anonymous):

but the middle part was wrong..

OpenStudy (anonymous):

2(x-10)(x+10)? that is correct, it just needs to be (2x-10)(x+10)

OpenStudy (anonymous):

2x^2 + 20x - 10x - 100

OpenStudy (anonymous):

is what you get when you use foil

hero (hero):

2(x^2 + 5x - 50) 2(x^2 + 10x - 5x - 50) 2(x(x + 10) - 5(x + 10)) 2((x - 5)(x + 10)) 2(x - 5)(x + 10)

OpenStudy (anonymous):

that works too

OpenStudy (anonymous):

so i just had my signs backwards

hero (hero):

@tyler123456789, I don't know if anything you posted was correct.

hero (hero):

@D_ what I posted are the proper factoring steps. It's called factor by grouping.

hero (hero):

There are other factoring methods, but this one is the most appropriate to use. It is also the most computational and shows the complete set of steps.

OpenStudy (anonymous):

ok so now i have to set it equal to zero so it would be x=5, x=-10 ?

hero (hero):

I see now. Yes, those are the zeroes.

OpenStudy (anonymous):

alrighty now i think i got it , thank you !

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