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PLEASEEEEEEE HELPPP What is the vertex in the quadratic function y = - 4x^2 + 8x - 3 ? Write your answer as an ordered pair.
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First do x=-b/2a
first coordinate of the vertex is always \(-\frac{b}{2a}\) which in your case is \(-\frac{8}{2\times -4}=1\)
You can plug in the 1 for x and solve for y
I GOT 1.5 ?
not likely
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\[ y = - 4x^2 + 8x - 3\] \[-4+8-3=?\]
1
recheck your math
is it -1 ?
no
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You're close though
y= -4(1)^2 - 8(1) -3
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