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OpenStudy (iesmee):
In the triangle below, what ratio is the csc θ? A. the ratio 5 over 13 B. the ratio 12 over 13 C. the ratio 13 over 12 D. the ratio 13 over 5
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OpenStudy (iesmee):
OpenStudy (anonymous):
sin(x) = opp/hyp csc(x) = 1/(sinx) csc(x) = hyp/opp csc(theta) = 13/12
OpenStudy (iesmee):
:O thank you
OpenStudy (anonymous):
np
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