Question

What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

Answer 1

`a_(n)=2(4)^(n-1)`

`a_(n)=4(2)^(n-1)`

`a_(n)=2(n)^4`

`a_n=4(n)^2`

Answer 2

The first term is 4, and it's multiplying by 2.
So for the second term, it would be 4*2
For the third term, it would be 4*2^2.

For the nth term, it would be \[4*2^{n-1}\]

Answer 3

so what would be my answer from my option that i wrote