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Solve 8x^2 = 128 by factoring. Select one: a. {-4, 4} b. {-8, 8} Incorrect c. {-8, 8} Incorrect d. 8
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C.
Its incorrect ?
its correct.
It has the solutions $$\pm 8$$
I already tried it and it was wrong!!
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Well its not.
B and C are the same thing .
I'm a try D.
Since A doesn't work
8x^2 = 128 x^2 = 16 x = +- 4
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its a
to many powers of 2
lol
:)
so its not d
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its a 8x^2 = 128 divide each side by 8 x^2 = 16 what are two numbers where if you square them you get 16?
-4 and 4
yeah ur right thanks :) @zzr0ck3r
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