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The formula for a geometric sequence is an = 25(2) n − 1. What is the 3rd term of the sequence? help me please somebody
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Perhaps question should be [a_{n} = 25(2n-1) Given \[a_{n} = 25(2n-1)\] In order to find 3rd term of the given sequence put n=3 so we find \[a_{3} = 25(2n-1)=25(2\times3-1)=25(6-1)=25\times5=125\] therefore third term = 125
Perhaps question should be \[a_{n} = 25(2n-1)\]
i dont get it
so is it 75
The formula for a geometric sequence is an = 25(2) n − 1. What is the 3rd term of the sequence? Answer 50 150 75 100
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this is mii question
let n=3 ... and work the math
and it helps if you notate it correctly an = 25 2^(n-1)
dnt gt it
then you really need to go review the basics of your material .....
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