Question

What are the solutions of 2x^2 - 3 = 29?

A) ± 16
B) ± 4
C) ± 8
D) ± 13

Answer 1

you can start by adding 3 on both sides

Answer 2

so you have

2x^2 -3 +3 = 29 + 3
2x^2 = 32

Answer 3

Now divide by 2 and you have

2x^2 = 32
-- ---
2 2

x^2 = 16

Answer 4

now you can equal the equation to 0 and you have
x^2 - 16 = 0 you have the equation as (a^2-b^2) = (a+b)(a-b)

Answer 5

so you have
(x-4)(x+4) = 0 so x equal to -4 and 4

Answer 6

thank you

Answer 7

your welcome :)

Hope you understood explanation