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cos(2arccos1/3)=? please can you answear?
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\[\large \cos\left(2\color{royalblue}{\arccos\frac{1}{3}}\right)\] \[\large \color{royalblue}{\arccos\frac{1}{3}=\theta} \qquad\rightarrow\qquad \cos \theta=\frac{1}{3}=\frac{adjacent}{hypotenuse}\] We can draw a triangle to express this Trig function.|dw:1374617596367:dw|
Since this is your first question I feel I should ask, Is the formatted math text showing up ok on your screen? If you're using Internet Explorer it might just show up as a bunch of ugly code.
no no thanks a lot bro
hmm? :o
Anyway, we can label the sides of our triangle given cosine of the angle.|dw:1374617870931:dw|Then we want to use the Pythagorean Theorem to solve for the missing side.
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