1. Your are given the circuit below which contains four resistors R1 = 1.0 . , R2 = 4.0 . , R3 = 4.0 . , R4 = 5.0 . , and one capacitor C1 = 2.0 µF.

(a) What is the current through the resistor R4?
(b) What is the potential difference across the capacitor?
(c) What is the charge on the capacitor?
(d) What is the power dissipated by resistor R4?

Question

1. Your are given the circuit below which contains four resistors R1 = 1.0 . , R2 = 4.0 . , R3 = 4.0 . , R4 = 5.0 . , and one capacitor C1 = 2.0 µF. 




(a) What is the current through the resistor R4? 
(b) What is the potential difference across the capacitor? 
(c) What is the charge on the capacitor? 
(d) What is the power dissipated by resistor R4?

theeric · Answer

The circuit itself is very important. How the components are connected defines the current and such. Please include a circuit diagram to help with these.

anonymous · Answer

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theeric · Answer

So this is the circuit?|dw:1374682763112:dw|

radar · Answer

The current would be total 2 Amps, R4 is in series so 2 amps would be the current thru R4.
The potential difference across the capacitor would be the same as the voltage across R4, the IR voltage drop or 2X5 = 10 volts.  The power dissipated  by R4 would be ExI = 20 watts.  Charge of C is Q=CV|dw:1374700820653:dw|