PLEASEEEE HELP!!! A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec. The function h(t)= - 4.9t^2+6t+50, where h(t) is the height of the bird at time t. How long does the worm have before he is eaten?

Question

PLEASEEEE HELP!!! A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec.  The function h(t)= - 4.9t^2+6t+50, where h(t) is the height of the bird at time t. How long does the worm have before he is eaten?

anonymous · Answer

So the worm is on the ground.... So the height = 0 at the time right...

So factor that and find the roots using the quadratic formula...? what did you get?

anonymous · Answer

whats the formula

anonymous · Answer

$$\frac{ -6 \pm \sqrt{ (-6)^{2} -4(-4.9)(50)} }{ -9.8 }$$