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please help me!? Identify the excluded value for the rational function. y= 4/(x-1) A. 2 B. 3 C. 0 D. 1
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solve \(x-1=0\) in one step add one to both sides
x= 1?
That would be correct "excluded values" occur when the denominator = 0....so x - 1 = 0 when you add 1 to both sides you have x = 1 so yes ...good work! :)
thank you so much!! :)
yes \(x=1\)
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